Outty Ranking59
SeoulFrom $480
100% Private Full Day City Tour With Car
15 Reviews
Chris Hyosang Lee
Chris Hyosang Lee runs 3 experiences we rank, across 1 city. Their average Outty Ranking is 53.9 out of 100, their strongest tour is 100% Private Full Day City Tour With Car at 59, and prices start at $460 per person.
- Experiences
- 3
- Avg Outty Ranking
- 53.9
- In the 90+ Club
- 0
- Traveler rating
- 4.93
- Reviews
- 21
- Free cancellation
- 100%
Traveler sentiment
Not enough reviews yet. Across 21 traveler reviews on their experiences, the weighted average is 4.93 out of 5.
Ratings and review counts are supplied by Viator and Tripadvisor travelers.
Review depth
Roughly 7 reviews per experience. Deeper review counts make the Outty Ranking more confident, which is why lightly reviewed tours are pulled toward the city average.
Cancellation flexibility
100% of their experiences (3 of 3) offer free cancellation, typically up to 24 hours ahead. Average length of an experience is 7.3 hours.
Top ranked Chris Hyosang Lee experiences
| Experience | Outty Ranking | Rating | Duration | Price |
|---|---|---|---|---|
| 100% Private Full Day City Tour With Car | 59 | 4.9 (15) | 8h | $480 |
| Half-day Private DMZ Tour for busy travelers | 54 | 5 (5) | 6h | $460 |
| Customizing Private Tour in Seoul with Car | 49 | 5 (1) | 8h | $500 |
Where Chris Hyosang Lee operates
All 3 experiences from Chris Hyosang Lee
Chris Hyosang Lee questions, answered
- How many experiences does Chris Hyosang Lee run?
- Outty ranks 3 bookable experiences from Chris Hyosang Lee across 1 city.
- Is Chris Hyosang Lee well reviewed?
- Travelers have left 21 reviews across their experiences, averaging 4.93 out of 5. Sentiment reads as not enough reviews yet.
- Does Chris Hyosang Lee offer free cancellation?
- 3 of their 3 experiences (100%) can be canceled free of charge, usually up to 24 hours before the start time.
- What is the best Chris Hyosang Lee experience?
- 100% Private Full Day City Tour With Car scores 59 out of 100 on the Outty Ranking, the highest of anything we rank from this operator.