Outty Ranking57
BrugesFrom $40
Food tasting & Historical walk
51 Reviews
Latin Tours Brugge
Latin Tours Brugge runs 3 experiences we rank, across 1 city. Their average Outty Ranking is 46.9 out of 100, their strongest tour is Food tasting & Historical walk at 57, and prices start at $25 per person.
- Experiences
- 3
- Avg Outty Ranking
- 46.9
- In the 90+ Club
- 0
- Traveler rating
- 4.30
- Reviews
- 58
- Free cancellation
- 67%
Traveler sentiment
Mostly positive. Across 58 traveler reviews on their experiences, the weighted average is 4.30 out of 5.
Ratings and review counts are supplied by Viator and Tripadvisor travelers.
Review depth
Roughly 19 reviews per experience. Deeper review counts make the Outty Ranking more confident, which is why lightly reviewed tours are pulled toward the city average.
Cancellation flexibility
67% of their experiences (2 of 3) offer free cancellation, typically up to 24 hours ahead. Average length of an experience is 2.2 hours.
Top ranked Latin Tours Brugge experiences
| Experience | Outty Ranking | Rating | Duration | Price |
|---|---|---|---|---|
| Food tasting & Historical walk | 57 | 4.4 (51) | 2.5h | $40 |
| Evening Delights: Bruges Tour with Beer & Chocolate | 42 | 3.6 (7) | 2h | $115 |
| Bruges: The sweetest chocolate walking tour for all ages | 42 | New | 2h | $25 |
Where Latin Tours Brugge operates
All 3 experiences from Latin Tours Brugge
Latin Tours Brugge questions, answered
- How many experiences does Latin Tours Brugge run?
- Outty ranks 3 bookable experiences from Latin Tours Brugge across 1 city.
- Is Latin Tours Brugge well reviewed?
- Travelers have left 58 reviews across their experiences, averaging 4.30 out of 5. Sentiment reads as mostly positive.
- Does Latin Tours Brugge offer free cancellation?
- 2 of their 3 experiences (67%) can be canceled free of charge, usually up to 24 hours before the start time.
- What is the best Latin Tours Brugge experience?
- Food tasting & Historical walk scores 57 out of 100 on the Outty Ranking, the highest of anything we rank from this operator.