Outty Ranking60
ZakynthosFrom $63
Zakynthos: Full-Day 2 in 1 Yacht Cruise to Kefalonia
4 Reviews
Cavo Grosso
Cavo Grosso runs 5 experiences we rank, across 1 city. Their average Outty Ranking is 52.0 out of 100, their strongest tour is Zakynthos: Full-Day 2 in 1 Yacht Cruise to Kefalonia at 60, and prices start at $40 per person.
- Experiences
- 5
- Avg Outty Ranking
- 52.0
- In the 90+ Club
- 0
- Traveler rating
- 3.67
- Reviews
- 6
- Free cancellation
- 100%
Traveler sentiment
Not enough reviews yet. Across 6 traveler reviews on their experiences, the weighted average is 3.67 out of 5.
Ratings and review counts are supplied by Viator and Tripadvisor travelers.
Review depth
Roughly 1 reviews per experience. Deeper review counts make the Outty Ranking more confident, which is why lightly reviewed tours are pulled toward the city average.
Cancellation flexibility
100% of their experiences (5 of 5) offer free cancellation, typically up to 24 hours ahead. Average length of an experience is 6 hours.
Top ranked Cavo Grosso experiences
| Experience | Outty Ranking | Rating | Duration | Price |
|---|---|---|---|---|
| Zakynthos: Full-Day 2 in 1 Yacht Cruise to Kefalonia | 60 | 4.5 (4) | 9h | $63 |
| 5-Hour Yacht Cruise around Zakynthos & Shipwreck | 59 | 4.5 (2) | 5h | $46 |
| Zakynthos Half Day Cruise Shipwreck Beach and Blue Caves | 49 | 1 (2) | 4h | $40 |
Where Cavo Grosso operates
3 of 5 experiences from Cavo Grosso
Cavo Grosso questions, answered
- How many experiences does Cavo Grosso run?
- Outty ranks 5 bookable experiences from Cavo Grosso across 1 city.
- Is Cavo Grosso well reviewed?
- Travelers have left 6 reviews across their experiences, averaging 3.67 out of 5. Sentiment reads as not enough reviews yet.
- Does Cavo Grosso offer free cancellation?
- 5 of their 5 experiences (100%) can be canceled free of charge, usually up to 24 hours before the start time.
- What is the best Cavo Grosso experience?
- Zakynthos: Full-Day 2 in 1 Yacht Cruise to Kefalonia scores 60 out of 100 on the Outty Ranking, the highest of anything we rank from this operator.