Outty Ranking76
StockholmFrom $24
Stockholm Old Town Walking Tour with Local Guide
63 Reviews
Amiketours
Amiketours runs 3 experiences we rank, across 1 city. Their average Outty Ranking is 64.1 out of 100, their strongest tour is Stockholm Old Town Walking Tour with Local Guide at 76, and prices start at $24 per person.
- Experiences
- 3
- Avg Outty Ranking
- 64.1
- In the 90+ Club
- 0
- Traveler rating
- 4.71
- Reviews
- 68
- Free cancellation
- 100%
Traveler sentiment
Consistently positive. Across 68 traveler reviews on their experiences, the weighted average is 4.71 out of 5.
Ratings and review counts are supplied by Viator and Tripadvisor travelers.
Review depth
Roughly 23 reviews per experience. Deeper review counts make the Outty Ranking more confident, which is why lightly reviewed tours are pulled toward the city average.
Cancellation flexibility
100% of their experiences (3 of 3) offer free cancellation, typically up to 24 hours ahead. Average length of an experience is 3.2 hours.
Top ranked Amiketours experiences
| Experience | Outty Ranking | Rating | Duration | Price |
|---|---|---|---|---|
| Stockholm Old Town Walking Tour with Local Guide | 76 | 4.7 (63) | 2h | $24 |
| Stockholm: 2h Old Town Walking Tour + 2.5h Archipelago Cruise | 63 | 5 (4) | 4.5h | $65 |
| Stockholm: 2h Old Town Tour + 1h Silent Electric Boat Cruise | 54 | 4 (1) | 3h | $89 |
Where Amiketours operates
All 3 experiences from Amiketours
Amiketours questions, answered
- How many experiences does Amiketours run?
- Outty ranks 3 bookable experiences from Amiketours across 1 city.
- Is Amiketours well reviewed?
- Travelers have left 68 reviews across their experiences, averaging 4.71 out of 5. Sentiment reads as consistently positive.
- Does Amiketours offer free cancellation?
- 3 of their 3 experiences (100%) can be canceled free of charge, usually up to 24 hours before the start time.
- What is the best Amiketours experience?
- Stockholm Old Town Walking Tour with Local Guide scores 76 out of 100 on the Outty Ranking, the highest of anything we rank from this operator.