Best overall
Adventurous Scavenger Hunt in Harrisburg by Operation City Quest
Highest Outty Ranking in the city right now.
Outty Ranking 49 · from $10
We rank 9 experiences in Harrisburg, United States, and compare the top 9 on ranking, price, length, and traveler rating. The strongest overall is Adventurous Scavenger Hunt in Harrisburg by Operation City Quest at 49 out of 100, the lowest entry price is $10 per person, and 0 experiences sit in the Outty 90+ Club. Traveler ratings shown here are provided by Viator and Tripadvisor.
Best overall
Highest Outty Ranking in the city right now.
Outty Ranking 49 · from $10
Most proven
The deepest traveler review history of anything we rank here.
Outty Ranking 46 · from $10
| Experience | Outty Ranking | Verdict | From | Duration | Traveler rating | Cancellation |
|---|---|---|---|---|---|---|
| Adventurous Scavenger Hunt in Harrisburg by Operation City Quest | 49 | Worth a Look | $10 | 2h | 4.0/5 (2) | Free to 24h before |
| Fun City Scavenger Hunt in Harrisburg by Wacky Walks | 47 | Worth a Look | $10 | 2h | 5.0/5 (1) | Free to 24h before |
| Harrisburg's Historic Downtown Smartphone Guided Walking Tour | 46 | Worth a Look | $10 | 1.2h | 4.0/5 (4) | Free to 24h before |
| Harrisburg City Scavenger Hunt by Crazy Dash | 44 | Worth a Look | $10 | 2h | Not yet rated | Free to 24h before |
| Private transfer from MDT airport to Harrisburg, Lancaster, York, Hershey | 38 | Worth a Look | $150 | 1h | 5.0/5 (1) | Free to 24h before |
| Astounding Scavenger Hunt: Capitol Reflections | 36 | Worth a Look | $12 | 2h | 3.0/5 (2) | None |
| Scavenger Hunt in Harrisburg by Zombie Scavengers | 35 | Worth a Look | $20 | 1h | Not yet rated | Free to 24h before |
| Astounding Bar Hunt: Harris-bars & Harris-beers Harrisburg | 34 | Worth a Look | $12 | 2h | Not yet rated | None |
| Harrisburg Scavenger Hunt Adventure | 27 | Worth a Look | $50 | 3h | Not yet rated | None |
Traveler ratings and review counts are provided by Viator and Tripadvisor. The Outty Ranking is our own evaluation and is calculated independently of them.